हिन्दी में पढ़ेंHome › Formulas › Kinematics › Projectile — maximum height
Projectile — maximum height
H = u² sin²θ / 2g
Where: H = maximum height (m) / heat (J), g = acceleration due to gravity (m/s²), θ = angle, u = initial velocity (m/s)
Solved example
Given: g = 7, theta = 45°, u = 10
Find: H (maximum height (m) / heat (J))
- Formula: H = u²·sin(θ)²/(2·g)
- Substitute the values: H = 10²·sin(45°)²/(2·7)
- Result: H = 3.571429 m
Answer: H = 3.571429 m
Calculator
How to calculate Projectile — maximum height
- Write down the formula: H = u² sin²θ / 2g.
- Note the known values (g, θ, u).
- Substitute them and simplify to find H.
- Use the calculator above to solve for any letter.
Frequently asked questions
What is the formula for Projectile — maximum height?
The formula is H = u² sin²θ / 2g, where H = maximum height (m) / heat (J), g = acceleration due to gravity (m/s²), θ = angle, u = initial velocity (m/s).
What is Projectile — maximum height when g = 7, theta = 45°, u = 10?
H = 3.571429 m. Substitute the values into H = u² sin²θ / 2g and simplify.