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Rhombus of a Quadrilaterals & polygons
diagonals bisect at 90°; 4a² = d₁² + d₂²
Where: a = side a, d₁ = d₁, d₂ = d₂
Use the same units for all lengths (e.g. all in cm); areas come out in cm², volumes in cm³.
Solved example
Given: d_1 = 7, d_2 = 5
Find: a (side a)
- Formula: 4·a² = d₁² + d₂²
- Rearranged for a: a = √(d₁² + d₂²)/2
- Substitute the values: a = √(5² + 7²)/2
- Rearranged for a: a = -√(d₁² + d₂²)/2
- Substitute the values: a = -√(5² + 7²)/2
- Result: a = 4.301163 ; a = -4.301163
Answer: a = 4.301163
Calculator
How to calculate Rhombus of a Quadrilaterals & polygons
- Write down the formula: diagonals bisect at 90°; 4a² = d₁² + d₂².
- Note the known values (d₁, d₂).
- Substitute them and simplify to find a.
- Use the calculator above to solve for any letter.
Frequently asked questions
What is the formula for Rhombus of a Quadrilaterals & polygons?
The formula is diagonals bisect at 90°; 4a² = d₁² + d₂², where a = side a, d₁ = d₁, d₂ = d₂.
What is Rhombus of a Quadrilaterals & polygons when d_1 = 7, d_2 = 5?
a = 4.301163. Substitute the values into diagonals bisect at 90°; 4a² = d₁² + d₂² and simplify.